If p/q is a rational root of the given polynomial, then p is a divisor of the constant term, 15, and q is a divisor of the leading coefficient, 5.
So, p = ±(1, 3, 5, 15) and q = ±(1, 5). Therefore, the only possible rational roots are ±(1, 1/5, 3, 3/5, 5, 15). Thus, 1/3 is not possible as a rational root for the given polynomial.
ANSWER: A