Philip P. answered 12/15/14
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0 = -3x2 + 3x + 9
Use the quadratic formula:
x = (-b/2a) ± (1/2a)√(b2-4ac)
Where a is the coefficient of the x2 term, b is the coefficient of the x term and c is the constant term, In your case, a=-3, b=3,c=9:
x = (3/6) ± (1/6)√(32-4(-3)(9))
x = 1/2 ± (1/2)√117
x = 1/2 ± (1/6)√9*13
x = 1/2 ± (1/2)√13
Use your calculator to compute the approximate value of the √13 to get the two answers.