
Mitiku D. answered 12/14/14
Tutor
4.9
(205)
Electrical Engineer, Patient and Objective
Hi Noelle,
Yes you do have to use some integral. But the problem is more of a test of your on graphs than calculus.
Once you are able to graph it and shade the area of interest it will be straightforward evaluation of integrals.
Your graph is bounded by y=7 from the top, y=x from the left and y=x^2/28 from the left.
Divide your shaded area vertically in to two regions at x=7
Find the area on the left by integrating the square function and subtracting it from the area of the triangle
Find the area under the square function and subtract it from the area of the square (on second taught you may not have to break up the area. You can just integrate the sqr w/t 0 and 14 as the upper limit and subtract that from the sum of the square and the triangle)
I hope this helps

Imtiazur S.
12/28/14