Miche W. answered 12/11/14
Tutor
0
(0)
Creative, understanding math tutor with 10+ years in classroom
A = Average of snacks made by Adrian
D = Average of snacks made byDakota
C = Average of snacks made byCalvin
These are averages, so you need to add the individual rates and divide by the number of entries. Then work the system of equations.
A+D+C = 52 A+D = 61 D+C = 44
3 2 2
A+D+C=52(3) A+D = 61(2) D+C = 44(2) Now solve in terms of the common variable of the last two
A+D+C=156 A+D = 122 D+C = 88 equations. That being the D.
A= 122-D C = 88-D Now substitute these values into the first equation.
(122-D)+D+(88-D)=156 And now you have only one variable the D. Solve:
122+88-2D+D=156
210 - D = 156
-D = -54
D = 54
Now substitute in D to solve for the other values.
A+D = 122 D+C=88
A+54= 122 54+C=88
A = 68 C = 34
Check:
A+D+C = 52 68 + 54 + 34 = 52
3 3
3 3
156 = 52
3
52 = 52 √
Adrian averaged 68 snacks
Dakota averaged 54 snacks
Calvin averaged 34 snacks