Sam Z. answered 05/17/19
Math/Science Tutor
8hrs
worker rate=200e^(-.5t)uph
conveyer=50uph
p=2.71828182...
200*2.72^(-.5*2)=
2 hrs=200*.3678=73.576
8hrs=200*2.72^(-.5*8)=
200*.018=3.66
Diana D.
asked 05/16/19At a processing plant, over the course of an 8-hour day, workers move material into a pile, which is removed at a constant rate by a conveyor belt. The workers move material into the pile at rate 200e−0.5t
units/hr while the conveyor belt removes the material at 50 units/hr.
(a) Find the net change in the size of the pile over the first 2 hours, and over the first 8 hours. Round your answers to the nearest hundredth.
| 2 hours = units |
| 8 hours = units |
(b) At what time is the amount of material in the pile the largest and the smallest?
| largest | t = |
| smallest | t = |
Sam Z. answered 05/17/19
Math/Science Tutor
8hrs
worker rate=200e^(-.5t)uph
conveyer=50uph
p=2.71828182...
200*2.72^(-.5*2)=
2 hrs=200*.3678=73.576
8hrs=200*2.72^(-.5*8)=
200*.018=3.66
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