The volume element is dv=π((4x)2-(4x2)2)dx and you have to integrate this from x=0 to x=1
I got v=-16π( x5/5 -x3/3)which has to be evaluated between 0 and 1.
Can you do that?
Jim
Ckecse B.
asked 05/16/19y = 4x4, y = 4x, x ≥ 0; about the x-axis
The volume element is dv=π((4x)2-(4x2)2)dx and you have to integrate this from x=0 to x=1
I got v=-16π( x5/5 -x3/3)which has to be evaluated between 0 and 1.
Can you do that?
Jim
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