The rectangle always has one side = to x2; the other side is 6-x.
A=(6-x)x2
dA/dx= 12x-3x2.=0...exclude x= 0 and you get your answer!
El M.
asked 05/16/19A rectangle is constructed under the graph off(x) =x2 with one corner at ( 6, 0) and one corner on the graph of f(x) = x2 (0≤x≤6).
Represent the area A of the rectangle as a
function of x: A(x)=
What value of x will maximize the area of the
rectangle? Maximum area when x=
The rectangle always has one side = to x2; the other side is 6-x.
A=(6-x)x2
dA/dx= 12x-3x2.=0...exclude x= 0 and you get your answer!
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