One Number is three less than a second number twice the second number is two less and four times the first find the two numbers

Answer 1

I may not be interpreting your question correctly, but I believe you're saying (with x as the first number and y as the second) that

x = y - 3

2y = 4x - 2

Solving this system of equations can be done through substitution, plugging in x = y - 3 to the second equation. This results in

2y = 4y - 12 - 2

Solving this results in y = 7

Plugging in y = 7 into x = y - 3, gives x = 7 - 3,

so x = 4