
Mark M. answered 12/09/14
Tutor
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Mathematics Teacher - NCLB Highly Qualified
(2(1) + 7 ) + (2(2) + 7) + (2(3) + 7 ) + (2(4) + 7)
2 + 7 + 4 + 7 + 6 + 7 + 8 + 7
48
The formula is
Sn = (n/2)(2a1 + (n - 1)d), where S = the sum, n = number of terms, a1 = first term, d= common difference.
S4 = (4/2)[2(9) + (4 - 1)2]
S4 = 2[18 + 6]
S4 = 2(24)
S4 = 48