
Patrick B. answered 05/13/19
Math and computer tutor/teacher
x + 5y = 240
x = 240 - 5y
x*y = (240 - 5y)y =
240y - 5y^2 = f(y)
f'(y) = 240 - 10y
f'(y) = 0 when y = 24
which forces x = 240 = 24*5 = 240 - 120 = 120
the max product is 24*120 = 2880
Ana A.
asked 05/13/19The sum of one number, x, and 5 times another number, y, is 240. Find the two number x and y, that give the maximum possible product x·y.
Patrick B. answered 05/13/19
Math and computer tutor/teacher
x + 5y = 240
x = 240 - 5y
x*y = (240 - 5y)y =
240y - 5y^2 = f(y)
f'(y) = 240 - 10y
f'(y) = 0 when y = 24
which forces x = 240 = 24*5 = 240 - 120 = 120
the max product is 24*120 = 2880
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