2 Answers By Expert Tutors
Dibyendu D. answered • 05/20/19
Tutor
4.8
(64)
2+ years of experience in teaching high-school and middle-school math
∫ (y-x)/(y+x) dx
= ∫ [(2y)/(y+x) -1] dx
= ∫ (2y)/(y+x) dx - ∫dx
= 2y ∫ 1/(y+x) dx - x + C
= 2y ∫ 1/(y+x) d(y+x) - x + C
= 2y loge(y+x) - x + C
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Paul M.
05/12/19