
Patrick B. answered 05/19/19
Math and computer tutor/teacher
x is the speed of the wind
t is the time with the wind
5-t is the time against the wind
then
250+x is the speed with the wind
250 - x is the speed against the wind
576 = (250 + x)* t = (250 - x)*(5- t)
250t + xt = 1250 - 250t - 5x + xt <--- distributive on left; FOIL on right
250t = 1250 - 250t - 5x <---- subtracts xt from both sides
500t = 1250 - 5x <---- adds 250t to both sides
t = (5/2) - (1/100) * x <--- divides both sides by 500
Substitutes into the first equation
576 = (250 +x)( 5/2 - (1/100)x ]
= 625 - (5/2)x + (5/2)x - (1/100)x^2 <--- FOILs again
= 625 - (1/100)x^2 <---- combines like terms; (5/2)x cancels out
-49 = -(1/100)x^2 <---- subtracts 625 from both sides
4900 = x^2 <--- multiplies both sides by -100
x = 70
then t = (5/2 + 70/100) = (5/2 + 7/10) = 64/20 = 32/10 = 3.2 hours = 3 hours and 12 minutes
against the wind: 576/(250-70) = 576/180 = 3.2 hours
with the wind: 576/(250+70) = 576/320 = 1.8 hours = 1 hour and 48 minutes
The speed of the wind is definitely 70 km/hr