Tom N. answered 05/09/19
Strong proficiency in elementary and advanced mathematics
Let leakout = 8900 cc/min. Height of the cone = 7m radius of the cone at top = 2.75m Volume of the cone
V = πr2h/3. Using similar triangles in the cone r/2.75 =h/7 so r= 2.75h/7 now V= πh3(2.75/7)2/3 V=πh3(.154).
V= .051πh3 and dV/dt = .153πh2dh/dt where dh/dt = 18c/min. This now yields dV/dt = 175.2x104cc/min for the fill. To find the rate at which water is being pumped into the tank add the leak rate so that the rate is equal
to 1.75x104 cc/min + .89x104cc/min which gives 176.09x104 cc/min