Patrick B. answered 05/27/19
Math and computer tutor/teacher
We need to know where x^2 > 5x+6 on x=[1,infinity],
x^2 - 5x - 6 > 0
( x - 6 )( x + 1 ) > 0
THe solutions are x=6 and x = -1
Sign table:
interval x < -1 -1 < x < 6 x > 6
sample x -2 0 7
result 8 -6 8
so for x=[1,6), x^2 < 5x+6
and for x(6,infinity) x^2 > 5x+6
since the function is decreasing, g(x^2) > g(5x+6) for the first inequality and
g(x^2) < g(5x+6) for the second inequality
So the solution is [1,6)