How do I integrate 3X^2+2x+5/x^2?

Answer 1

∫(3x² + 2x + 5/x²) dx

∫3x² dx + ∫2x dx + ∫5/x² dx

3∫x² dx + 2∫x dx + 5∫x^-2 dx

3[x²⁺¹/2+1] + 2[x¹⁺¹/1+1] + 5[x^-2+1/-2+1]

3[x³/3] + 2[x²/2] + 5[x^-1/-1]

x³ + x² - 5/x + C

Answer 2

∫[(3x² + 2x + 5) / x²]dx

= ∫[3 + 2/x + 5x^-2]dx

= 3x + 2lnlxl - 5/x + C