Solve the system of equations using the elimination method

Question

-3x+4y=12

2x+y=-8

Answer 1

Equation #1: -3x + 4y = 12

Equation #2: 2x + y = -8

Let's use the substitution method for Equation #2 to determine what Y equals:

2x + y = -8

y = -8 - 2x

Now that we know what Y is equal to, let's apply this formula to Equation #1 and solve:

-3x + 4(-8 - 2x) = 12

-3x -32 - 8x = 12

-11x -32 = 12

-11x = 44

x = -4

Now that we know what X equals, let's place the X into any one of the equations and solve. I choose Equation #1:

2(-4) + y = -8

-8 + y = -8

y = 0

To ensure we did it right, let's check our work:

Equation #1: -3(-4) + 4(0) = 12

12 + 0 = 12

12 = 12 CORRECT

Equation #2: 2(-4) + (0) = -8

-8 + 0 = -8

-8 = -8 CORRECT

Therefore, the answer to the system of equations is X = -4 & Y = 0, or (-4,0)