Hi Madison,
First lets find the maximum height.
the height function will follow the path of a parabola and the vertex of the parabola will be the highest point
we can find the t value of the vertex using the formula
-b/2a where a and b are the coefficients of the equation
b = 64
a = -16
t = -64/2(-16)
t = -64/-32
t = 2
now evaluate the function at that point to get maximum height
-16(2)2 + 64(2) + 3 = 67
so the maximum height will be 67 ft above the ground
now to find the time when it returns to the ground we need to set the equation to 0 and solve for t
-16t2 + 64t + 3 = 0
use the quadratic formula to solve since we can't factor
t = (-b - sqrt(b2 -4ac))/2a ( it is really + or - the SQRT but I couldn't represent that
t = (-64 - sqrt(4096 - (-192)))/-32
t = (-64 - 65.4828)/-32
t = -129.4828/-32
t = 4.046338 seconds ( time when the ball will hit the ground
Hope this helps