A rectangular room is doubled in size by adding x meters to the length and x meters to the width of the room. If the original room had an area of 1015 meters, what is the value of x?

Answer 1

1015 = L * w = Lw

2030 = (L+x)(w+x)

= Lw + Lx + wx + x^2

2030 = 1015 + (L+w)x + x^2

1015 = (L+w)x + x^2

x^2 + (L+w)x - 1015 = 0

x = [-(L+w) +or- sqrt ( (L+w)^2 + 4060 )] / 2