Zeeshan I. answered 04/20/19
Calc 1, 2 and 3 teacher for 2 years
ƒ''(x) = 7 - 9x + 8x2
Integrating, we get
ƒ'(x) = ∫ (7 - 9x + 8x2) dx + C
ƒ'(x) = 7x - 9/2 x2 + 8/3 x3 + C
Using the condition 𝑓′ (0) = −4, we have C = -4. Therefore
ƒ'(x) = 7x - 9/2 x2 + 8/3 x3 - 4
Integrating again, we have
ƒ(x) = ∫ (7x - 9/2 x2 + 8/3 x3 - 4) dx + D
ƒ(x) = 7/2 x2 - 3/2 x3 + 2/3 x4 - 4x + D
Using the condition 𝑓(0) = 9, we have D = 9. Therefore
ƒ(x) = 7/2 x2 - 3/2 x3 + 2/3 x4 - 4x + 9
or
ƒ(x) = 9 - 4x + 7/2 x2 - 3/2 x3 + 2/3 x4