6 times a number increased by 17 is 19

Question

can u tell me the variable,equation,and solution for this problem

Answer 1

Yobani,

 You can set up the problem like this:

 

the variable can be anything you want the unknown number to be; in this case we'll call it "x".

 

6 times "x" increased by (plus) 17 is (equals) 19

 

so:

 

6x + 17 = 19

 

now, solve this algebraicly by solving for the "x"

 

first subtract 17 from both sides to get the 6x on one side, usually the left side, and we get

 

6x = 2

 

 now, let's isolate the "x" on the left side by dividing both sides by 6 and we get

 

x = 2/6 factored down to 1/3 

 

subsitute 1/3 for the x and let's see what we get

 

6(1/3) + 17 = 19

 

2 + 17 = 19, so we are right that x = 2/6 or 1/3 

Answer 2

Hello Yobani,

 

The equation would be 6x+17=19

 

6x=2  by moving the 17 over to the other side 

 

x=(2/6)  by dividing both sides by 6

 

x=(1/3) can always check your work by plugging the result back into the original equation.

 

Hope this helped!