Patrick B. answered 04/19/19
Math and computer tutor/teacher
y = x^4 - 8x^3 = x^3( x - 8)
x intercepts are zero and 8. zero is solution of multiplicity 3
y intercept at (0,0)
derivative: y' = 4x^3 - 24x^2 = 4x^2 ( x - 6)
critical values are x=0 of multiplicity 2, and x=6
again, that's (0,0) and (6,-432)
2nd derivative: y'' = 12x^2 - 48x = 12x( x- 4)
inflection points x=0 and x=4
(0,0) and (4, -256)