Matthew B. answered 04/17/19
Cheap and likes teaching.
Note that P ∨ ~P is a tautology, so it isn't really needed here. Nevertheless,
P ⊃ ~M from 1
~M ⊃ ~C by modus tollens of 2
Notice that 3 is logically equivalent to ~C ⊃ ~L
Hence, by transitivity, P ⊃ ~L
By 4,
(~P ⊃ ~E) • (~E ⊃ ~C)
By transitivity, ~P ⊃ ~C
By 3,
~C ⊃ ~L
By transitivity,
~P ⊃ ~L
Hence, by 5, P ∨ ~P ⊃ ~L ∨ ~L
Finally, ~L ∨ ~L ≡ ~L.
I'll leave it to you to put it into formal notation. The key here was transitivity. When given an "or" statement (i.e. ∨), working out the full implications of both sides can lead to an immediate solution.