The notation in this editor may be a challenge but, here we go:
coth2x -1 = (1/tanh2x) -1 = (1 - tanh2x)/tanh2/x = sech2x/tanh2x = 1/(cosh2x tanh2x) = 1/sinh2x
Aaron H.
asked 04/11/19I need to prove it by showing work.
The notation in this editor may be a challenge but, here we go:
coth2x -1 = (1/tanh2x) -1 = (1 - tanh2x)/tanh2/x = sech2x/tanh2x = 1/(cosh2x tanh2x) = 1/sinh2x
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