Dilip C. answered 04/10/19
Success-oriented Tutor for Math with Graduate Engineering Degree
To find the optimum rent (that is maximum revenue), we have to set up a quadratic equation follows:
Revenue, y = rent x units rented. Based on the information given, the equation will be:
y = (348 + 6x) (120 - x)
where x is the integer change from 120 in units rented. It will be negative for increased rent and positive for lower rent.
So the quadratic is:
y = -6x^2 + 372x + 41760 (a=-6, b=372, c=41760)
The maxima of this parabola is given by: -b/2a = -372/2(-6) = 31
This means, the optimum units rented = 120 - 31 =89
At that level, the rent he needs to charge = 348 + 6 x 31 = $534
He will rent out only 89 units, but his revenue will be maximum