The chance of getting a 7 or above( 7,8 or 9) is 3/9 =1/3
For this to occur on all 3 dice would be 1/3 x1/3 x 1/3=1/27
Huma R.
asked 04/08/19Jin and hari are playing a game with 3 fair dice . , each with 9 faces and with numbers 1-9 written on the faces . If a person gets the number 7 or above on all three dice ., he wins the game . Assuming Jin goes first , what is the probability that Jin will win .
The chance of getting a 7 or above( 7,8 or 9) is 3/9 =1/3
For this to occur on all 3 dice would be 1/3 x1/3 x 1/3=1/27
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Huma R.
Thanks for the help but the answer is 27/53 . 1/27 is the chance that Jin will win on the first roll .,and that may not happen . The answer goes on to say that the chance he wins on second turn is 26/27•26/27•1/27. And if he still does not win then 26/27•26/27•26/27•26/27•1/27 . And then he solves by geometric sequence . How did he get these figures I don’t understand .04/08/19