Use linear approximation to approximate 1/0.252 as follows: Let f(x) = 1/x and find the equation of the tangent line to f(x) at a "nice" point near 0.252 . Then use this to approximate 1/0.252 .

Answer 1

Hey Ariel, I took the tangent at x = 0.25 and got a linear approximation of 3 and 7999/8000 or 3.999875. I would be happy to help you with problems like these from start to finish and I am currently running a 20% discount on my rate!