J.R. S. answered 04/04/19
Ph.D. in Biochemistry--University Professor--Chemistry Tutor
The Ozonol is not likely to be a suitable substitute for the original Dr. Chase ointment. The reason for this being that the original is much more concentrated in ZnO (zinc oxide) and in the phenol as well. You could probably make your own by purchasing pure ZnO, pure phenol and then some aloe or lanolin or some other base to put them in. The 18.6% w/w means that for every 100 grams of ointment, you have 18.6 g of ZnO. Same for 0.59% w/w phenol. In 100 grams of ointment, you'd have 0.59 g phenol. So, for example, to prepare 50 grams of ointment, you'd use 9.3 g of ZnO + 0.3 g phenol, + 40.4 g of base (aloe, lanolin, etc). Just go to your local pharmacy and ask if they sell the ingredients. Good luck.