The limit required is lim as x -> 0 of sin(2x)/tan(7x).
L'Hospital's rule gives lim x -> 0 of 2 cos(2x)/7 sec2(7x) = 2/7
Katie M.
asked 04/03/19The limit required is lim as x -> 0 of sin(2x)/tan(7x).
L'Hospital's rule gives lim x -> 0 of 2 cos(2x)/7 sec2(7x) = 2/7
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