William W. answered • 03/29/19
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None of those statements are true.
The vertical asymptote is when the denominator is zero. Setting x3 - 9 = 0 gives x3 = 9 or x = cubed root of 9 which is about 2.08.
The horizontal asymptote is y = 0 for rational functions where the denominator is lower degree than the numerator (like this one)
William W.
Yes, Again the vertical asymptotes are when the denominator is zero. Setting x^3 - 9x = 0, you can factor out an x to get x(x^2 - 9) = 0 and then you can factor x^2 -9 into (x + 3)(x - 3) so it becomes (x)(x + 3)(x - 3) = 0. Set each piece equal to zero so you get vertical asymptotes at x = 0, x = -3, and x = 3 making E true
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03/29/19
Diana R.
The actual equation is (3x)/(x^3 -9x). I accidentally forgot the other x, but thank you for answering. Would any of those statements be true with the real equation?03/29/19