Suppose that T is a linear operator and x, y are eigenvectors corresponding to different eigenvalues i.e. Tx=λx and Tx=μy with λ and μ nonzero and x,y nonzero vectors. Then let us assume that x and y satisfy the equation x+cy=0 where c is a nonzero constant (i.e. let us assume that x and y are linearly dependent). By applying the operator T on both sides we get Tx+cTy=0 which is the same as λx+cμy=0 and since x=-cy we obtain that -cλy+cμy=0. Equivalently, cy(μ-λ)=0 which can not be true since c is a nonzero constant, y is a nonzero vector and the eigenvalues λ,μ are not equal. Therefore, the vectors x,y are linearly independent.
How to prove that eigenvectors from different eigenvalues are linearly independent?
How can I prove that if I have $n$ eigenvectors from different eigenvalues, they are all linearly independent?
Follow
1
Add comment
More
Report
1 Expert Answer
Still looking for help? Get the right answer, fast.
Ask a question for free
Get a free answer to a quick problem.
Most questions answered within 4 hours.
OR
Find an Online Tutor Now
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.