162 = 81 * 2 = 34 * 2
logb 162 = 4*logb3 + logb2 = 4y+x
Katie M.
asked 03/25/19If logb2=x and logb3=y, evaluate the following in terms of x and y:
a.) logb162=
162 = 81 * 2 = 34 * 2
logb 162 = 4*logb3 + logb2 = 4y+x
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