y = -x + 3, (-2,-2)
we know that the above equation is in the form: y = mx + b, where m is the slope. Any line parallel to the given line will have the same slope (m = -1). To find the equation of the parallel line we use the slope and the point given in the problem (-2, -2). Since we have the slope and the points already given, we only need to look for the y- intercept(b).
-2 = -1(-2) + b ------>-2 = 2 + b ------->b = 4,
since we have all info already, we plug in the found values to y = mx + b,
y = -x + 4
