Mark M. answered 03/18/19
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
f(x) = 3x3 + 2x + 1
f(0) = 1, so f-1(1) = 0
f'(x) = 9x2 + 2, f'(0) = 2
(f-1(1))' = 1/ f'(0) = 1/2
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f(x) = 2x3 + 3x - 5
f(0) = -5, so f-1(-5) = 0
f'(x) = 6x2 + 3, f'(0) = 3
(f-1(-5))' = 1/ f'(0) = 1/3
In general, if f(a) = b, and f is a one to one differentiable function, then (f-1(b))' = 1 / f'(a)