
Francisco P. answered 11/17/14
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Rigorous Physics Tutoring
If a set of vectors are linearly dependent, then aA + bB + cC + dD = 0 with a, b, c, and d not all zeros.
aA + bB + cC + dD = 0
a[0,3,0,5] + b[2,-3,-1,-1] + c[2,21,8,33] + d[-2,6,4,4] = [0,0,0,0]
Equating components,
2b + 2c -2d = 0
3a -3b + 21c + 6d = 0
-b + 8c + 4d = 0
5a - b + 33c + 4d = 0
a = 5, b = 4, c = -1, and d = 3 would be a possible set to show linear dependence.