What is the integral of 1/(sec^2 X . Tan^2 X) dx?

Answer 1

Int [1/(secx*tanx)]dx = int [cosx*cosx/sinx}dx = int [cos²x/sinx]dx = int [(1-sin²x)/sinx]dx int [ (1/sinx) -(sin²x/sinx)]dx = int [cscx - sinx]dx. Please continue from here.