How do I prove that 1−sinxcosx=cosx1+sinx?

Answer 1

Do you mean 1 - sin(x) cos (x) = cos(x) + sin(x)?

If x = π, then

1 - sin(x) cos (x) = 1 - sin(π) cos (π) = 1 - (0)(-1) = 1-0 = 1

cos(x) + sin(x) = cos(π) + sin(π) = -1 + 0 = -1

Since 1 ≠ -1, this is untrue and cannot be proven as correct.