Symmeatra H.

asked • 11/13/14

Estimating Distance Traveled- Integral/Antiderivative Unit

An object has a velocity
v(t) = 4/t+45 ft/s. Use the interval [3, 13] with n = 5 and equal subintervals to compute the following approximations of the distance the object traveled. (Round your final answers to two decimal place.)

(a) Left-hand sum = ft

(b) Right-hand sum = ft

(c) average of the two sums = ft

1 Expert Answer

By:

Byron S. answered • 11/13/14

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Symmeatra H.

Where so we get the v value from?
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11/13/14

Symmeatra H.

**do
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11/13/14

Byron S.

The values of v come from the velocity function given:
v(t) = 4/t+45 ft/s
v(3) = 4/(3) + 45
v(5) = 4/(5) + 45
etc.
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11/13/14

Symmeatra H.

Thank you, I got it now!
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11/13/14

Byron S.

Excellent!
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11/13/14

Symmeatra H.

Could you assist with this last one as well, i am having a little trouble.
Find y(t) using the following information.
dy/dt= t^5 + 6e^t ; y(0) = 12
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11/13/14

Byron S.

dy/dt = t5 + 6et
 
By the Fundamental Theorem of Calculus,
y(t) = ∫ (t5 + 6et) dt
 
Using anti-derivatives,
y(t) = t6/6 + 6et + C
 
And your initial condition,
y(0) = 06/6 + 6 e0 + C = 12
 
Use that to solve for C, and the underlined expression is your answer (with a number in place of C).
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11/13/14

Symmeatra H.

ahhh that makes sense, thank you!
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11/13/14

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