Tom N. answered 03/28/19
Strong proficiency in elementary and advanced mathematics
let 470= 2 x+ y and A= x y then A= x(470 -2 x ) = 470 x -2 x2 A= 470 x - 2 x2 dA/dx =470- 4 x and d2A/dx2 = -4 let dA/dx =0 to maximize the equation so 0= 470 - 4 x and x =117.5 ft this is a maximum since the second derivative is negative and y=245 ft.