how to find dy/dx.

Question

y= ln x⁶ + log ₃ x - 10 e^x + 5^x

Answer 1

Since the terms are added together, you can differentiate them separately;

Term 1: ln x⁶ dy/dx = 6/x

Term 2: log₃x dy/dx = 1/(xln3)

Term 3: -10e^x dy/dx = -10e^x

Term 4: 5^x dy/dx = 5^x(ln5)