2k2+7k-4-0

Question

2k²+7k-4=0

Answer 1

if its solving by completing the square

1: 2k²+7k-4=0
———————
        2

2: k²+^7k⁄2 -2=0  carry over the -2 to the opposite side =   k²+^7k/2=2

make a perfect square trinomial  : k²+^7k/2+⁴⁹/16= 2+⁴⁹/16

now solve

(k+⁷/4)²=⁸¹/16

k+⁷/4=±√⁸¹/16

k=-⁷/4±√⁸¹/16

k=-⁷/4+⁹/4= ²/4= ¹/2

k=-⁷/4-⁹/4= -¹⁶/4= -4

message me to clarify anything you dont understand.

Answer 2

Solve by factoring:

 = (2k - 1)(k + 4)

= 2k² + -k +8k -4

= 2k² +7k - 4