Ralph L. answered 03/11/13
Tutor
4.5
(2)
Algebra I, II, Visual Basic, Beginning C++ tutor
a2 -10a + 36 = 0
a2 - 10a = -36
(a - 5)2 = -36 + 25
√((a - 5)2 ) = √(-11)
a - 5 = √(-11)
a = 5 ± √-11
since you're taking the square root of a negative number, we introduce ¡2 = -1
a = 5 ± √( -1 * 11)
replace -1 by ¡2
a = 5 ± √( ¡2 * 11)
a = 5 ± ¡√11