
Mark M. answered 03/08/19
Mathematics Teacher - NCLB Highly Qualified
35 = 50e70k
0.7 = e70k
ln 0.7 = 70k
Determine the value of k, then substitute into
a = 35e80k
Jane P.
asked 03/08/19The rate of decay of a radioactive substance is proportional to the amount of substance present at any time t. In
1840 there were 50 grams of the substance and in 1910 there were 35 grams. To the nearest thousandth of a
gram, how many grams of the substance remain in 1990?
Mark M. answered 03/08/19
Mathematics Teacher - NCLB Highly Qualified
35 = 50e70k
0.7 = e70k
ln 0.7 = 70k
Determine the value of k, then substitute into
a = 35e80k
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