Use the chain rule!!
5A4 (dA/dt) + 5B4 (dB/dt) = 0
Notice that you do not have a value for B which you need.
Use the initial equation to determine B from the given value of A.
Then substitute into the derivative equation and solve for dA/dt.
Ariel L.
asked 03/06/19two variables quantities A and B are found to be related by the equation given below.What is the rate of change dA/dt at the moment when A=3 and dB/dt=2? A^5+B^5=275
Use the chain rule!!
5A4 (dA/dt) + 5B4 (dB/dt) = 0
Notice that you do not have a value for B which you need.
Use the initial equation to determine B from the given value of A.
Then substitute into the derivative equation and solve for dA/dt.
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