
Jason U. answered 02/27/19
Computer Science (M.Sc.) and Mathematics (B.Sc.) Tutor of 10+yrs
First you must employ the composite argument properties that are applicable to the terms in the equation. Here, the left-hand side (LHS) consists of two such terms: sin(θ+90) and cos(θ+180). We will transform LHS into the right-hand side (RHS) of the equation to show equality.
The first is of the form sin(a+b) which has the composite argument a+b and is equal to sin(a)*cos(b)+cos(a)*sin(b).
The second is of the form cos(a+b) which also has the composite argument a+b and is equal to cos(a)*cos(b)-sin(a)*sin(b).
Thus:
LHS = [ sin(θ)*cos(90)+cos(θ)*sin(90) ] - [ cos(θ)*cos(180)-sin(θ)*sin(180) ]
= sin(θ)*cos(90) + cos(θ)*sin(90) - cos(θ)*cos(180) + sin(θ)*sin(180)
(factoring out sin(θ) and cos(θ))
= sin(θ) * [cos(90) + sin(180)] + cos(θ) * [sin(90) - cos(180)]
(with: cos(90)=0=sin(180), sin(90)=1, cos(180)=-1)
= sin(θ) * [ 0 + 0 ] + cos(θ) * [ 1 - (-1) ]
= cos(θ) * 2 = 2cos(θ) = RHS.
QED.