
Patrick B. answered 02/23/19
Math and computer tutor/teacher
length * width = area
3w(w) = 56
w^2 = 56/3
w = sqrt(56/3)
= sqrt( 56*3/ (3*3)) <--- rationalizes the denominator
= sqrt( 56*3) /sqrt(9)
= sqrt( 56*3)/ 3
= sqrt( 2*2*2*3*7) / 3
= 2 * sqrt(2*3*7)/3
= 2 * sqrt(42)/3
which is APPROXIMATELY 4.32049379893857348731+
multiplying by 3 gives the length. Doing so cancels the 3 in the denominator.
So the length is 2 * sqrt(42), which is APPROXIMATELY 12.96148139681572+
So the area is:
2 * Sqrt(42)/3 * 2 * sqrt(42) = 4 * 42/3 = 4 * 14 = 56