Keith M. answered 11/06/14
Tutor
New to Wyzant
Keith - Tutoring mathematics from middle up to college mathematics
Hi Kim
First we need to find the slope of the line between line 1.
We use the formula:
y2 - y1 / x2 - x1
-2 - 1 / -7 - (-3) ---> this gives us -3 / -4 or simply 3/4. So our slope for line 1 is 3/4.
Now using the formula, (y - y1) = m (x - x1) we find the line.
(y - 1) = 3/4 (x - (-3)) ---> (y - 1) = 3/4x + 9/4.
Now we add one to each side to get y = 3/4x + 13/4.
Now for line 2, we use the same process and formulas.
Find the slope of line 2.
4 - (-1) / 8 - 2 gives us 5/6. Our slope for line 2 is 5/6.
(y - (-1)) = 5/6 (x - 2).
(y + 1) = 5/6x - 5/3 ---> now subtract one from both sides to get...
y = 5/6x - 8/3.
Since the two lines do not have the same slope or the negative reciprocal of one slope being the other, the two lines through the given points are neither parallel nor are they perpendicular.
NEITHER