Find [hog](x) g(x)=x-2 h(x)=3x^2+1

Answer 1

h(g(x)) aka h o g is found by plugging into g(x) into h(x) wherever you see an x in h(x). Since g(x) is "x-2", plug "x-2" into h(x) where you see an x so: 3(x-2)² + 1

This could be multiplied out to be 3x² -12x +13 but that seems like extra work that's not really needed.