Y = 1 - 2cos(x)
y(pi/2) = 1-2cos(pi/2) = 1
John N.
asked 02/19/19Find the particular solution to y ' = 2sin(x) given the general solution is y = C − 2cos(x) and the initial condition .
Y = 1 - 2cos(x)
y(pi/2) = 1-2cos(pi/2) = 1
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