Patrick B. answered 02/19/19
Math and computer tutor/teacher
(2/3)x^(-1/3) + (2/3) y^(-1/3) y' = 0
(2/3) y^(-1/3) y' = (-2/3)x^(-1/3)
y^(-1/3) y' = -x^(-1/3)
y' = -x^(-1/3)/y^(-1/3)
y' = y^(1/3)/x^(1/3) = (y/x)^(1/3)
the slope is -1/3(sqrt(3)) = -sqrt(3)/9
B = y - mx
= 1 - (-sqrt(3)/9)*(3 * sqrt(3)
= 1 - -3/3 = 1 + 1 = 2
y = (-sqrt(3)/9) x + 2