Find an equation in slope intercept form

Question

1/4, -1/2 and 3/4, 1

solve problem need help

Answer 1

(1/4, -1/2) and (3/4, 1)

are 2 points on a straight line with slope = (1+1/2)/(3/4 -1/4) = (3/2)/(1/2) = 3

slope = change in y divided by change in x = (y2-y1)/(x2-x1)

the line's equation is

y -1 = 3(x-3/4) in point slope form (you can use either point. y-y1 = m(x-x1))

y= 3x -9/4 +1

y = 3x -5/4

4y = 12x -5

12x -4y = 5 in standard form (ax +by = c)

or

12x -4y -5 = 0 in general form

or

y = 3x + b where b = y intercept. plug in either point to solve for b

1 = 3(3/4) +b

b = 1-9/4 = -5/4

y = 3x -5/4 in slope intercept form

Answer 2

The slope is 3/2 divided by 1/2 = 3

B = y - mx

= 1 - (3)(3/4)

= 1 - 9/4

-5/4

y = 3x - 5/4